C program to find LCM of two numbers

PROGRAM-1:

LCM using while loop and if statement

#include <stdio.h>

int main()

{

    int n1, n2, minMultiple;

    printf("Enter two positive integers: ");

    scanf("%d %d", &n1, &n2);

    minMultiple = (n1>n2) ? n1 : n2;

    while(1)

    {

        if( minMultiple%n1==0 && minMultiple%n2==0 )

        {

            printf("The LCM of %d and %d is %d.", n1, n2,minMultiple);

            break;

        }

        ++minMultiple;

    }

    return 0;

}

OUTPUT:

Enter two positive integers: 72

120

The LCM of 72 and 120 is 360.

.

PROGRAM-2:

LCM calculation by finding GCD

#include <stdio.h>

int main()

{

    int n1, n2, i, gcd, lcm;

    printf("Enter two positive integers: ");

    scanf("%d %d",&n1,&n2);

    for(i=1; i <= n1 && i <= n2; ++i)

    {

        if(n1%i==0 && n2%i==0)

            gcd = i;

    }

    lcm = (n1*n2)/gcd;

    printf("The LCM of two numbers %d and %d is %d.", n1, n2, lcm);

    return 0;

}

OUTPUT:

Enter two positive integers: 72

120

The LCM of 72 and 120 is 360.