C program to find GCD of two numbers

PROGRAM-1:

GCD using for loop and if statement


#include <stdio.h>
int main()
{
    int n1, n2, i, gcd;
 
    printf("Enter two integers: ");
    scanf("%d %d", &n1, &n2);
 
    for(i=1; i <= n1 && i <= n2; ++i)
    {
        if(n1%i==0 && n2%i==0)
            gcd = i;
    }
 
    printf("G.C.D of %d and %d is %d", n1, n2, gcd);
 
    return 0;
}


PROGRAM-2:

GCD using while loop and if...else statement


#include <stdio.h>
int main()
{
    int n1, n2;
    
    printf("Enter two positive integers: ");
    scanf("%d %d",&n1,&n2);
 
    while(n1!=n2)
    {
        if(n1 > n2)
            n1 -= n2;
        else
            n2 -= n1;
    }
    printf("GCD = %d",n1);
 
    return 0;
}

OUTPUT:

Enter two positive integers: 81
153
GCD = 9


PROGRAM-3:


GCD for both positive and negative numbers


#include <stdio.h>
int main()
{
    int n1, n2;
 
    printf("Enter two integers: ");
    scanf("%d %d",&n1,&n2);

    n1 = ( n1 > 0) ? n1 : -n1;
    n2 = ( n2 > 0) ? n2 : -n2;
 
    while(n1!=n2)
    {
        if(n1 > n2)
            n1 -= n2;
        else
            n2 -= n1;
    }
    printf("GCD = %d",n1);
 
    return 0;
}

OUTPUT:

Enter two integers: 81
-153
GCD = 9